Unit 4 — Calibration Procedure and Calculations
TM-CAL-003 — Open Handout TM Chapters: Chapter 5, Appendix A ELOs: Execute calibration procedure; compute error and determine pass/fail Estimated time: 30 minutes
Step 1: Read the TM
Open TM-CAL-003. Read Chapter 5 and Appendix A completely.
Then come back here.
Chapter 5 — Calibration Procedure
5-1. INITIAL FREQUENCY CALIBRATION
- Connect GPSDO 10 MHz output to frequency counter via 50 Ω BNC cable.
- Allow GPSDO to lock completely (GPS fix acquired + 15 min warm-up).
- Measure output frequency. Should read 10.000000 ±0.010 MHz within 5 minutes of lock.
- If frequency is off by more than 1 Hz, check Si5351 crystal frequency setting in firmware. The on-board crystal may be 25.000 or 26.000 MHz; verify and update firmware constant.
- Monitor frequency for 30 minutes. Deviation from 10.000000 should be 0.1 Hz over 24 hours indicates PLL loop filter or crystal aging issue.
- Compare to WWV at 10 MHz using zero-beat method (see TM-CAL-001). Agreement within 1 Hz confirms NIST traceability.
Appendix A — Formulas
Si5351A output frequency
fout = fxtal × PLL_mult / (output_divider)
PPM error from integer count
errorppm = (fmeasured − 10,000,000) / 10
Allan deviation (GPSDO estimate)
ADEV(τ = 1 s) ≈ 1×10−9 (crystal limited)
Key Formulas Summary
- fout = fxtal × PLL_mult / (output_divider)
- errorppm = (fmeasured − 10,000,000) / 10
- ADEV(τ = 1 s) ≈ 1×10−9 (crystal limited)
The Calibration Procedure
Chapter 5 specifies 6 calibration steps.
Calibration is a comparison: you apply a known reference value to the instrument under test and record what the instrument reads. The difference is the error. You then either: - Adjust the instrument until the error is within the acceptance criterion, or - Record the error as a correction factor to apply to future readings
An error criterion found in Chapter 5: 50 Ω. Confirm the exact criterion in the TM.
Practice Problems
Work these before checking answers.
P4-1. The reference value is 10.000 V. Your instrument reads 10.043 V. (a) What is the error in volts? (b) What is the error as a percentage of the reference value? Show your work.
P4-2. Using the formula for % error: error% = (measured − reference) / reference × 100 Apply it to: reference = 100.0 kHz, measured = 99,985 Hz. (a) Error in Hz. (b) Error in %. (c) Error in ppm.
P4-3. The acceptance criterion in the TM is ±1%. Your measurement gives an error of +0.8%. Does it pass? State your reasoning.
Practice Problem Answers
P4-1. (a) 10.043 − 10.000 = +0.043 V (b) 0.043 / 10.000 × 100 = +0.43%
P4-2. (a) 99,985 − 100,000 = −15 Hz (b) −15 / 100,000 × 100 = −0.015% (c) −15 / 100,000 × 1,000,000 = −150 ppm
P4-3. +0.8% is within ±1%. PASS. State: "error = +0.8%; criterion = ±1%; result = PASS." Always cite the TM section for the criterion.
Self-Check Questions
SC4-1. How many steps does Chapter 5 specify for the calibration procedure?
SC4-2. What reference value(s) does Chapter 5 apply to the instrument under test?
SC4-3. State the calibration acceptance criterion from the TM. Cite the section.
SC4-4. Write the error formula from Appendix A. Include units.
SC4-5. If the instrument reads 2.3% high, is the error positive or negative? What does a positive error indicate?
Answer Key
SC4-1. Count the numbered steps in Chapter 5. (TM Ch. 5)
SC4-2. See Chapter 5 for the reference values applied. These are the known-good inputs used to check the instrument. (TM §5-1)
SC4-3. See TM Chapter 5 or Chapter 7. Copy the criterion exactly with units and section number.
SC4-4. See Appendix A. Write it exactly as shown.
SC4-5. Positive (instrument reads higher than reference). A positive error means the instrument over-reads — it reports a value higher than the true value. (TM App. A)
Checkpoint
Before proceeding, you must be able to: - State the calibration acceptance criterion without looking - Write the error formula from memory - Work a % error and ppm calculation correctly
→ Proceed to Unit 5